What is the extreme g(x)=-50x^2+400x+500 ?

The extreme g(x)=-50x^2+400x+500 is Maximum(4,1300)

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extreme g(x)=-50x^2+400x+500

extreme points

g (x) = - 50 x^{2} + 400 x + 500

Maximum (4, 1300)

Solution steps

f^{'} (x) = - 100 x + 400

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 4

into

- 50 x^{2} + 400 x + 500 : 1300

Maximum (4, 1300)

f (x) = 4 x + 5 y

x^{11} - 3 x^{9} + 2

x^{3} - 2 x^{2} - 4 x - 4

9 x^{3} - 7 x^{2} + 3 x + 10

f (x) = 4 + 27 x - x^{3}

What is the extreme g(x)=-50x^2+400x+500 ?
The extreme g(x)=-50x^2+400x+500 is Maximum(4,1300)