en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^2-5x+2

Solution

extreme points

f (x) = 2 x^{2} - 5 x + 2

Solution

Minimum (\frac{5}{4}, - \frac{9}{8})

Solution steps

f^{'} (x) = 4 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{4},

Increasing

: \frac{5}{4} < x < \infty

Plug

x = \frac{5}{4}

into

2 x^{2} - 5 x + 2 : - \frac{9}{8}

Minimum (\frac{5}{4}, - \frac{9}{8})

Popular Examples

extreme f(x)= x/(ln(x))[2.1]extreme points

f (x) = \frac{x}{ln ( x )} [2.1]

extreme f(x)=x^4-72x^2-2,-7<= x<= 7 extreme points

f (x) = x^{4} - 72 x^{2} - 2, - 7 \leq x \leq 7

extreme f(x)=x^2+10x^{2/3}extreme points

f (x) = x^{2} + 10 x^{\frac{2}{3}}

extreme y=-x^2+1-,1<= x<= 2 extreme points

y = - x^{2} + 1 -, 1 \leq x \leq 2

extreme f(x)=3x^4-12x^3-60x^2+4 extreme points

f (x) = 3 x^{4} - 12 x^{3} - 60 x^{2} + 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-5x+2 ?
The extreme f(x)=2x^2-5x+2 is Minimum(5/4 ,-9/8)