What is the extreme f(x)=((x-ln(x)))/x ?

The extreme f(x)=((x-ln(x)))/x is Minimum(e,(e-1)/e)

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extreme f(x)=((x-ln(x)))/x

extreme points

f (x) = \frac{( x - ln ( x ) )}{x}

Minimum (e, \frac{e - 1}{e})

Solution steps

f^{'} (x) = \frac{ln ( x ) - 1}{x ^{2}}

Find intervals:

Decreasing

: 0 < x < e,

Increasing

: e < x < \infty

Plug

x = e

into

\frac{x - ln ( x )}{x} : \frac{e - 1}{e}

Minimum (e, \frac{e - 1}{e})

f (x, y) = e^{10 x^{2} + 4 y^{2} + 2}

f (x) = ln (x^{2} + 3 x + 8)

f (x) = 9 sin (3 x)

f (x, y) = 16 - 8 x + 10 y

f (x) = 20 sin (2 x)

What is the extreme f(x)=((x-ln(x)))/x ?
The extreme f(x)=((x-ln(x)))/x is Minimum(e,(e-1)/e)