en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-2x^2+200x

Solution

extreme points

f (x) = - 2 x^{2} + 200 x

Solution

Maximum (50, 5000)

Solution steps

f^{'} (x) = - 4 x + 200

Find intervals:

Increasing

: - \infty < x < 50,

Decreasing

: 50 < x < \infty

Plug

x = 50

into

- 2 x^{2} + 200 x : 5000

Maximum (50, 5000)

Popular Examples

extreme y=x^2-5x-14 extreme points

y = x^{2} - 5 x - 14

extreme sqrt(x)*7-x extreme points

x \cdot 7 - x

extreme f(x)=-5x^2-8y^2-2xy+102y extreme points

f (x) = - 5 x^{2} - 8 y^{2} - 2 x y + 102 y

extreme f(x)=x^{2/3},-1<= x<= 8 extreme points

f (x) = x^{\frac{2}{3}}, - 1 \leq x \leq 8

extreme 2x^3-3x^2-72x+1 extreme points

2 x^{3} - 3 x^{2} - 72 x + 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^2+200x ?
The extreme f(x)=-2x^2+200x is Maximum(50,5000)