What is the extreme (4e^{-2x})/(2x+5) ?

The extreme (4e^{-2x})/(2x+5) is Maximum(-3,-4e^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme (4e^{-2x})/(2x+5)

extreme points

\frac{4 e ^{- 2 x}}{2 x + 5}

Maximum (- 3, - 4 e^{6})

Solution steps

Find the critical points:

x = - 3

Domain of

\frac{4 e ^{- 2 x}}{2 x + 5} : x < - \frac{5}{2} or x > - \frac{5}{2}

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < - \frac{5}{2},

Decreasing

: - \frac{5}{2} < x < \infty

Plug the extreme point

x = - 3

into

\frac{4 e ^{- 2 x}}{2 x + 5} \Rightarrow y = - 4 e^{6}

Maximum (- 3, - 4 e^{6})

f (x, y) = - 2 x^{2} - y^{3} + 9 y^{2} + 16 x - 15 y + 5

f (x) = 2 x^{2} + \frac{91.2}{x}

P (a) = y^{2} - 4 r^{2} + r + e^{2}

f (t) = 25 cos (2 t)

f (x) = - 2 x^{3} + 24 x^{2} - 42 x + 7

What is the extreme (4e^{-2x})/(2x+5) ?
The extreme (4e^{-2x})/(2x+5) is Maximum(-3,-4e^6)