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Popular >

midpoint (-8,4),(3,-4)

Solution

midpoint

(- 8, 4), (3, - 4)

Solution

(- \frac{5}{2}, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 8, 4), (x_{2}, y_{2}) = (3, - 4)

= (\frac{3 - 8}{2}, \frac{- 4 + 4}{2})

Refine

= (- \frac{5}{2}, 0)

Popular Examples

inverse of f(x)= 1/2 x^3+1/2 inverse

f (x) = \frac{1}{2} x^{3} + \frac{1}{2}

inverse of f(x)=x^4+1 inverse

f (x) = x^{4} + 1

domain of f(x)=sqrt((x-2)/(x-1))domain

f (x) = \frac{x - 2}{x - 1}

range of f(x)=(x-3)/(3x+5)range

f (x) = \frac{x - 3}{3 x + 5}

parity f(x)=sqrt(1-x)parity

f (x) = 1 - x

Frequently Asked Questions (FAQ)

What is the midpoint (-8,4),(3,-4) ?
The midpoint (-8,4),(3,-4) is (-5/2 ,0)