What is the extreme x^2-10x-9,2<= x<= 7 ?

The extreme x^2-10x-9,2<= x<= 7 is Maximum(2,-25),Minimum(5,-34),Maximum(7,-30)

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extreme x^2-10x-9,2<= x<= 7

extreme points

x^{2} - 10 x - 9, 2 \leq x \leq 7

Maximum (2, - 25), Minimum (5, - 34), Maximum (7, - 30)

Solution steps

Find the critical points:

x = 2, x = 5, x = 7

Domain of

x^{2} - 10 x - 9, 2 \leq x \leq 7 : 2 \leq x \leq 7

Find intervals:

Decreasing

: 2 < x < 5,

Increasing

: 5 < x < 7

Plug the extreme point

x = 2

into

x^{2} - 10 x - 9 \Rightarrow y = - 25

Maximum (2, - 25)

Plug the extreme point

x = 5

into

x^{2} - 10 x - 9 \Rightarrow y = - 34

Minimum (5, - 34)

Plug the extreme point

x = 7

into

x^{2} - 10 x - 9 \Rightarrow y = - 30

Maximum (7, - 30)

Maximum (2, - 25), Minimum (5, - 34), Maximum (7, - 30)

0.002 x^{2} + 4.4 x - 90

f (x) = 7 - 4 x^{2}

f (x, y) = \frac{( 1 x + 3 y )}{1 + x ^{2} + y ^{2}}

x^{2} + y^{2} - 2 x + 26

f (x) = - 1.25 x^{2} + 160 x - 2500

What is the extreme x^2-10x-9,2<= x<= 7 ?
The extreme x^2-10x-9,2<= x<= 7 is Maximum(2,-25),Minimum(5,-34),Maximum(7,-30)