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Popular >

extreme f(x)=(x-2)^{1/8}

Solution

extreme points

f (x) = (x - 2)^{\frac{1}{8}}

Solution

Minimum (2, 0)

Solution steps

f^{'} (x) = \frac{1}{8 ( x - 2 ) ^{\frac{7}{8}}}

Find intervals:

Increasing

: 2 < x < \infty

Plug

x = 2

into

(x - 2)^{\frac{1}{8}} : 0

Minimum (2, 0)

Popular Examples

extreme y=2cos(x)-11x+7[-pi,0]extreme points

y = 2 cos (x) - 11 x + 7 [- π, 0]

extreme y=(x^2-4)^4(x^2+1)^5 extreme points

y = (x^{2} - 4)^{4} (x^{2} + 1)^{5}

extreme f(x)=((x^2-2x+1))/(x+1)extreme points

f (x) = \frac{( x ^{2} - 2 x + 1 )}{x + 1}

extreme f(x)=-x^3+6x^2-9x-1 extreme points

f (x) = - x^{3} + 6 x^{2} - 9 x - 1

extreme f(x)=(-1/100 (x)(x-300))extreme points

f (x) = (- \frac{1}{100} (x) (x - 300))

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x-2)^{1/8} ?
The extreme f(x)=(x-2)^{1/8} is Minimum(2,0)