What is the extreme f(x)=2x+6,-4<= x<= 2 ?

The extreme f(x)=2x+6,-4<= x<= 2 is Minimum(-4,-2),Maximum(2,10)

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extreme f(x)=2x+6,-4<= x<= 2

extreme points

f (x) = 2 x + 6, - 4 \leq x \leq 2

Minimum (- 4, - 2), Maximum (2, 10)

Solution steps

Find the critical points:

x = - 4, x = 2

Domain of

2 x + 6, - 4 \leq x \leq 2 : - 4 \leq x \leq 2

Find intervals:

Increasing

: - 4 < x < 2

Plug the extreme point

x = - 4

into

2 x + 6 \Rightarrow y = - 2

Minimum (- 4, - 2)

Plug the extreme point

x = 2

into

2 x + 6 \Rightarrow y = 10

Maximum (2, 10)

Minimum (- 4, - 2), Maximum (2, 10)

f (x) = (x - 9)^{3}

f (x) = 1 - x^{\frac{4}{5}}

f (x) = 4 + 5 x + x^{2}

- 2 x + 3 ln (4 x), 1 \leq x \leq 5

f (x) = \frac{( - x ^{6} - 5 x ^{3} + 5 x )}{( x ^{2} + 2 )}

What is the extreme f(x)=2x+6,-4<= x<= 2 ?
The extreme f(x)=2x+6,-4<= x<= 2 is Minimum(-4,-2),Maximum(2,10)