What is the extreme f(x)=10000e^{0.17(x-1.62)^2} ?

The extreme f(x)=10000e^{0.17(x-1.62)^2} is Minimum(1.62,10000)

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extreme f(x)=10000e^{0.17(x-1.62)^2}

extreme points

f (x) = 10000 e^{0.17 (x - 1.62)^{2}}

Minimum (1.62, 10000)

Solution steps

f^{'} (x) = 3400 e^{0.17 (x - 1.62)^{2}} (x - 1.62)

Find intervals:

Decreasing

: - \infty < x < 1.62,

Increasing

: 1.62 < x < \infty

Plug

x = 1.62

into

10000 e^{0.17 (x - 1.62)^{2}} : 10000

Minimum (1.62, 10000)

f (x, y) = \frac{5 x}{1 + x ^{2} + y ^{2}}

f (x) = x^{3} - 4 x + 6

f (x) = x^{3} - 4 x + 3

f (x) = \frac{x}{2} - 3 sin (\frac{x}{3}), 0 \leq x \leq 2 π

f (x, y) = 81 - (x^{2} + y^{2})

What is the extreme f(x)=10000e^{0.17(x-1.62)^2} ?
The extreme f(x)=10000e^{0.17(x-1.62)^2} is Minimum(1.62,10000)