What is the extreme f(x)=5+(8+5x)^{2/5} ?

The extreme f(x)=5+(8+5x)^{2/5} is Minimum(-8/5 ,5)

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extreme f(x)=5+(8+5x)^{2/5}

extreme points

f (x) = 5 + (8 + 5 x)^{\frac{2}{5}}

Minimum (- \frac{8}{5}, 5)

Solution steps

f^{'} (x) = \frac{2}{( 5 x + 8 ) ^{\frac{3}{5}}}

Find intervals:

Decreasing

: - \infty < x < - \frac{8}{5},

Increasing

: - \frac{8}{5} < x < \infty

Plug

x = - \frac{8}{5}

into

5 + (8 + 5 x)^{\frac{2}{5}} : 5

Minimum (- \frac{8}{5}, 5)

f (x) = x^{2} y - 2 x y + 2 y^{2} x

f (x) = x e - 4 x^{2}

e^{x} + \frac{1 - x}{e ^{x}}

y = f (x) = x (x - 1)^{5}

y = \frac{e ^{(2 - x)} + x ^{2} - x}{2}

What is the extreme f(x)=5+(8+5x)^{2/5} ?
The extreme f(x)=5+(8+5x)^{2/5} is Minimum(-8/5 ,5)