What is the extreme f(x)=0.00324x^2-0.501x+33.684 ?

The extreme f(x)=0.00324x^2-0.501x+33.684 is Minimum((0.501)/(0.00648),14.31663…)

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extreme f(x)=0.00324x^2-0.501x+33.684

extreme points

f (x) = 0.00324 x^{2} - 0.501 x + 33.684

Minimum (\frac{0.501}{0.00648}, 14.31663 \dots)

Solution steps

f^{'} (x) = 0.00648 x - 0.501

Find intervals:

Decreasing

: - \infty < x < \frac{0.501}{0.00648},

Increasing

: \frac{0.501}{0.00648} < x < \infty

Plug

x = \frac{0.501}{0.00648}

into

0.00324 x^{2} - 0.501 x + 33.684 : 14.31663 \dots

Minimum (\frac{0.501}{0.00648}, 14.31663 \dots)

f (x, y) = (x - y)^{2} - x^{4} - y

f (x) = x^{3} - x^{2} - x + 9, - 1 \leq x \leq 2

f (x, y) = x^{2} + y^{2} - 2 x + 4 y

r - s - 1

w (x, y) = x e^{2} y + e - y

What is the extreme f(x)=0.00324x^2-0.501x+33.684 ?
The extreme f(x)=0.00324x^2-0.501x+33.684 is Minimum((0.501)/(0.00648),14.31663…)