What is the extreme f(x)=4-x,-3<= x<= 3 ?

The extreme f(x)=4-x,-3<= x<= 3 is Maximum(-3,7),Minimum(3,1)

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extreme f(x)=4-x,-3<= x<= 3

extreme points

f (x) = 4 - x, - 3 \leq x \leq 3

Maximum (- 3, 7), Minimum (3, 1)

Solution steps

Find the critical points:

x = - 3, x = 3

Domain of

4 - x, - 3 \leq x \leq 3 : - 3 \leq x \leq 3

Find intervals:

Decreasing

: - 3 < x < 3

Plug the extreme point

x = - 3

into

4 - x \Rightarrow y = 7

Maximum (- 3, 7)

Plug the extreme point

x = 3

into

4 - x \Rightarrow y = 1

Minimum (3, 1)

Maximum (- 3, 7), Minimum (3, 1)

f (x, y) = (x^{2} - 9)^{2} + (y^{2} - 36)^{2}

f (x) = - 3 x^{2} - 12 x + 24 y^{2} + 12 y = 0

f (x) = 7 x - 5

ln (x) - 7 x + 11

f (x, y) = 3 - x^{2} - y^{2} + 6 y

What is the extreme f(x)=4-x,-3<= x<= 3 ?
The extreme f(x)=4-x,-3<= x<= 3 is Maximum(-3,7),Minimum(3,1)