What is the extreme f(x)=100x+100y-x^2-y^2 ?

The extreme f(x)=100x+100y-x^2-y^2 is Maximum(50,50)

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extreme f(x)=100x+100y-x^2-y^2

extreme points

f (x) = 100 x + 100 y - x^{2} - y^{2}

Maximum (50, 50)

Solution steps

Find the critical points:

(50, 50)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(50, 50) :

Maximum

Maximum (50, 50)

f (x) = x^{2} + y^{2} + 18 x - 4 y

f (x) = x^{3} - 9 x^{2}, - 1 \leq x \leq 7

f (x, y) = x^{2} + y^{2} + 9

f (x, y) = x^{2} + y^{2} - 2 x + 2

f (x) = 2 + 9 x + 3 x^{2} - x^{3}, - 2 \leq x \leq 6

What is the extreme f(x)=100x+100y-x^2-y^2 ?
The extreme f(x)=100x+100y-x^2-y^2 is Maximum(50,50)