What is the extreme (x^3)/3-x^2-35x+4 ?

The extreme (x^3)/3-x^2-35x+4 is Maximum(-5, 337/3),Minimum(7,-527/3)

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extreme (x^3)/3-x^2-35x+4

extreme points

\frac{x ^{3}}{3} - x^{2} - 35 x + 4

Maximum (- 5, \frac{337}{3}), Minimum (7, - \frac{527}{3})

Solution steps

f^{'} (x) = x^{2} - 2 x - 35

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 5

into

\frac{x ^{3}}{3} - x^{2} - 35 x + 4 : \frac{337}{3}

Maximum (- 5, \frac{337}{3})

Plug

x = 7

into

\frac{x ^{3}}{3} - x^{2} - 35 x + 4 : - \frac{527}{3}

Minimum (7, - \frac{527}{3})

Maximum (- 5, \frac{337}{3}), Minimum (7, - \frac{527}{3})

f (x, y) = e^{6 x^{2} + 4 y^{2} + 10}

f (x, y) = x y - 8 x - y^{2} + 12 x + 160

f (x, y) = x^{2} + 3 y^{2} - y^{3} - 4 x

f (x) = 0.4 x^{2} + 110.2 x, 0 \leq x

f (x) = \frac{( 3 x )}{( 9 - x ^{2} )}, - 3 \leq x \leq 2

What is the extreme (x^3)/3-x^2-35x+4 ?
The extreme (x^3)/3-x^2-35x+4 is Maximum(-5, 337/3),Minimum(7,-527/3)