What is the extreme f(x,y)=3xy-4x-4y+3 ?

The extreme f(x,y)=3xy-4x-4y+3 is Saddle(4/3 , 4/3)

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extreme f(x,y)=3xy-4x-4y+3

extreme points

f (x, y) = 3 x y - 4 x - 4 y + 3

Saddle (\frac{4}{3}, \frac{4}{3})

Solution steps

Find the critical points:

(\frac{4}{3}, \frac{4}{3})

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 9

Check the sign of at each critical point

Check critical point

(\frac{4}{3}, \frac{4}{3}) :

Saddle

Saddle (\frac{4}{3}, \frac{4}{3})

h (x) = 5 - x^{2} (- 3.1)

f (x) = 4 csc (x)

S (v, t) = v \cdot t - \frac{v}{t} \cdot \frac{2 t ^{2}}{2}

f (x) = 2 x^{3} - 96 x - 3

x ln (\frac{x}{9}) - x

What is the extreme f(x,y)=3xy-4x-4y+3 ?
The extreme f(x,y)=3xy-4x-4y+3 is Saddle(4/3 , 4/3)