What is the shift f(x)=-cos(1/2 (x-pi/2))-2 ?

The shift f(x)=-cos(1/2 (x-pi/2))-2 is Phase: pi/2 , Vertical:-2

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shift f(x)=-cos(1/2 (x-pi/2))-2

shift

f (x) = - cos (\frac{1}{2} (x - \frac{π}{2})) - 2

Phase : \frac{π}{2}, Vertical : - 2

Solution steps

f (x) = - cos (\frac{1}{2} (x - \frac{π}{2})) - 2

g (B x - C) = cos (\frac{1}{2} (x - \frac{π}{2})), B = \frac{1}{2}, C = \frac{π}{4}, D = - 2

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{4}}{\frac{1}{2}}

\frac{π}{2}

The vertical shift

D

- 2

- 2

f (x) = - 2 sec (\frac{x}{2}) + 3

f (x) = x - 2 + 4

f (x) = (x^{2} - 8 x)^{2} - 8 (x^{2} - 8 x)

f (x) = \frac{x ^{2}}{4 x ^{2} + 7}

\frac{x ^{5}}{36 - x ^{2}}

What is the shift f(x)=-cos(1/2 (x-pi/2))-2 ?
The shift f(x)=-cos(1/2 (x-pi/2))-2 is Phase: pi/2 , Vertical:-2