What is the extreme 4+(9x-36)/(sqrt((x-4)^2+65)) ?

The extreme 4+(9x-36)/(sqrt((x-4)^2+65)) is None

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extreme 4+(9x-36)/(sqrt((x-4)^2+65))

extreme points

4 + \frac{9 x - 36}{( x - 4 ) ^{2} + 65}

None

Solution steps

f^{'} (x) = \frac{585}{( x ^{2} - 8 x + 81 ) x ^{2} - 8 x + 81}

Find intervals:

None

None

f (x) = \frac{- 125}{4} x^{4} + x

f (x) = ln (x^{2} - 6 x - 7)

f (x) = sin (2 π x)

f (x) = x^{2} + y + x y

y = 2 + 3 x - x^{3}

What is the extreme 4+(9x-36)/(sqrt((x-4)^2+65)) ?
The extreme 4+(9x-36)/(sqrt((x-4)^2+65)) is None