What is the extreme f(x)=8+(9+7x)^{2/7} ?

The extreme f(x)=8+(9+7x)^{2/7} is Minimum(-9/7 ,8)

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extreme f(x)=8+(9+7x)^{2/7}

extreme points

f (x) = 8 + (9 + 7 x)^{\frac{2}{7}}

Minimum (- \frac{9}{7}, 8)

Solution steps

f^{'} (x) = \frac{2}{( 7 x + 9 ) ^{\frac{5}{7}}}

Find intervals:

Decreasing

: - \infty < x < - \frac{9}{7},

Increasing

: - \frac{9}{7} < x < \infty

Plug

x = - \frac{9}{7}

into

8 + (9 + 7 x)^{\frac{2}{7}} : 8

Minimum (- \frac{9}{7}, 8)

f (x) = 6 x + 7 y

f (x, y) = x y - 3 x^{3} y^{2}

f (x, y, z) = x^{4} + y^{4} - 4 x y

f (x) = 40000 - 2 x^{2}

f (x) = x^{2} + y^{2} + 2 x - 6 y - 3

What is the extreme f(x)=8+(9+7x)^{2/7} ?
The extreme f(x)=8+(9+7x)^{2/7} is Minimum(-9/7 ,8)