What is (((y+1)b)/p)p+by ?

The solution to (((y+1)b)/p)p+by is 2by+b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (((y+1)b)/p)p+by

simplify

(\frac{( y + 1 ) b}{p}) p + b y

2 b y + b

Solution steps

(\frac{( y + 1 ) b}{p}) p + b y

Apply rule:

(a) = a

(\frac{( y + 1 ) b}{p}) = \frac{( y + 1 ) b}{p}

= \frac{( y + 1 ) b}{p} p + b y

Cross-cancel common factor:

p

= (y + 1) b + b y

= b (y + 1) + b y

Expand

b (y + 1) : b y + b

= b y + b + b y

Group like terms

= b y + b y + b

Add similar elements:

b y + b y = 2 b y

= 2 b y + b

f (x, y) = - 2 x^{2} + 3 y^{2}

f (x, y) = x^{3} + y^{2} + x y

f (x) = 54 x^{4} - 8 x

\frac{x ^{3}}{x ^{2} + x - 2}

f (x) = x^{4} + 18 x^{2} + 5, - 6 \leq x \leq 6