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Popular >

extreme f(x)= 8/(x^2-4)

Solution

extreme points

f (x) = \frac{8}{x ^{2} - 4}

Solution

Maximum (0, - 2)

Solution steps

f^{'} (x) = - \frac{16 x}{( x ^{2} - 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

\frac{8}{x ^{2} - 4} : - 2

Maximum (0, - 2)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)= 8/(x^2-4) ?
The extreme f(x)= 8/(x^2-4) is Maximum(0,-2)