What is the extreme f(x)=x^3-3x^2-9x+6 ?

The extreme f(x)=x^3-3x^2-9x+6 is Maximum(-1,11),Minimum(3,-21)

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extreme f(x)=x^3-3x^2-9x+6

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 6

Maximum (- 1, 11), Minimum (3, - 21)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 6 : 11

Maximum (- 1, 11)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 6 : - 21

Minimum (3, - 21)

Maximum (- 1, 11), Minimum (3, - 21)

f (x, y) = ln (4 x^{2} + 9 y^{2} - 36)

x^{3} - x^{2} - x + 2

x^{3} - x^{2} - x + 3

x^{3} - x^{2} - x + 4

x^{3} - x^{2} - x + 7

What is the extreme f(x)=x^3-3x^2-9x+6 ?
The extreme f(x)=x^3-3x^2-9x+6 is Maximum(-1,11),Minimum(3,-21)