What is the extreme f(x)=-1/2 x^2+15x-51 ?

The extreme f(x)=-1/2 x^2+15x-51 is Maximum(15, 123/2)

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extreme f(x)=-1/2 x^2+15x-51

extreme points

f (x) = - \frac{1}{2} x^{2} + 15 x - 51

Maximum (15, \frac{123}{2})

Solution steps

f^{'} (x) = - x + 15

Find intervals:

Increasing

: - \infty < x < 15,

Decreasing

: 15 < x < \infty

Plug

x = 15

into

- \frac{1}{2} x^{2} + 15 x - 51 : \frac{123}{2}

Maximum (15, \frac{123}{2})

f (x) = (x^{2} - \frac{1}{2}) e^{- 2 x}

f (x) = x^{2} + y^{2} - 16 = 0

2 x^{2} - 2 x^{2} y + y^{2}

x^{2} + x + 2

\frac{x - 5}{x ^{2} - 18 x + 81}

What is the extreme f(x)=-1/2 x^2+15x-51 ?
The extreme f(x)=-1/2 x^2+15x-51 is Maximum(15, 123/2)