What is the extreme f(x,y)=x^3y^2+2xy-5 ?

The extreme f(x,y)=x^3y^2+2xy-5 is None

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extreme f(x,y)=x^3y^2+2xy-5

extreme points

f (x, y) = x^{3} y^{2} + 2 x y - 5

None

Solution steps

Find the critical points:

None

x^{3} y^{2} + 2 x y - 5

has no critical points, therefore there are no extreme points

None

x^{6} - \frac{6}{5} x^{5}

P (x, y) = 0.3 + x^{2} + 0.2 y^{2} + 0.1 x y - 14 x - 10 y + 2000

f (x, y) = \frac{1}{2} x^{2} + \frac{1}{2} y^{2} - x^{2} y + 5

y = \frac{x ^{4}}{12} - \frac{x ^{3}}{2} + x^{2} + 10

f (x) = (x - 2)^{7} (x + 4)^{7}

What is the extreme f(x,y)=x^3y^2+2xy-5 ?
The extreme f(x,y)=x^3y^2+2xy-5 is None