What is the extreme f(x)=x^3-2x-4x+4(0.3) ?

The extreme f(x)=x^3-2x-4x+4(0.3) is Maximum(-sqrt(2),6.85685…),Minimum(sqrt(2),-4.45685…)

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extreme f(x)=x^3-2x-4x+4(0.3)

extreme points

f (x) = x^{3} - 2 x - 4 x + 4 (0.3)

Maximum (- 2, 6.85685 \dots), Minimum (2, - 4.45685 \dots)

Solution steps

f^{'} (x) = 3 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 2 x - 4 x + 40.3 : 6.85685 \dots

Maximum (- 2, 6.85685 \dots)

Plug

x = 2

into

x^{3} - 2 x - 4 x + 40.3 : - 4.45685 \dots

Minimum (2, - 4.45685 \dots)

Maximum (- 2, 6.85685 \dots), Minimum (2, - 4.45685 \dots)

x^{2} + x^{- 2}

(x - 3)^{2} (x - 2)

f (x) = 6 x^{2} - 6 x + 9

f (x) = 2 y^{2} + 2 x y + x^{2} - 16 x - 20 y

- \frac{2}{4 x + x ^{2} - 2}

What is the extreme f(x)=x^3-2x-4x+4(0.3) ?
The extreme f(x)=x^3-2x-4x+4(0.3) is Maximum(-sqrt(2),6.85685…),Minimum(sqrt(2),-4.45685…)