What is the extreme f(x)=2^{(x+0.528)}-10(x+0.528) ?

The extreme f(x)=2^{(x+0.528)}-10(x+0.528) is Minimum(3.32269…,-24.07999…)

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extreme f(x)=2^{(x+0.528)}-10(x+0.528)

extreme points

f (x) = 2^{(x + 0.528)} - 10 (x + 0.528)

Minimum (3.32269 \dots, - 24.07999 \dots)

Solution steps

f^{'} (x) = 0.69314 \dots \cdot 2^{x + 0.528} - 10

Find intervals:

Decreasing

: - \infty < x < 3.32269 \dots,

Increasing

: 3.32269 \dots < x < \infty

Plug

x = 3.32269 \dots

into

2^{x + 0.528} - 10 (x + 0.528) : - 24.07999 \dots

Minimum (3.32269 \dots, - 24.07999 \dots)

y = x^{2} - 5

- x^{2} - 4 x + 1

f (x) = 3 x^{3} - 24 x^{2} + 48 x - 6

\frac{5}{x + 1}

f (x) = \frac{( x - 1 ) ^{2}}{x ^{2} - 1}

What is the extreme f(x)=2^{(x+0.528)}-10(x+0.528) ?
The extreme f(x)=2^{(x+0.528)}-10(x+0.528) is Minimum(3.32269…,-24.07999…)