What is the extreme f(x)=(-x^2-10x-13)/(x+9) ?

The extreme f(x)=(-x^2-10x-13)/(x+9) is Minimum(-11,12),Maximum(-7,4)

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extreme f(x)=(-x^2-10x-13)/(x+9)

extreme points

f (x) = \frac{- x ^{2} - 10 x - 13}{x + 9}

Minimum (- 11, 12), Maximum (- 7, 4)

Solution steps

f^{'} (x) = \frac{- x ^{2} - 18 x - 77}{( x + 9 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 11,

Increasing

: - 11 < x < - 9,

Increasing

: - 9 < x < - 7,

Decreasing

: - 7 < x < \infty

Plug

x = - 11

into

\frac{- x ^{2} - 10 x - 13}{x + 9} : 12

Minimum (- 11, 12)

Plug

x = - 7

into

\frac{- x ^{2} - 10 x - 13}{x + 9} : 4

Maximum (- 7, 4)

Minimum (- 11, 12), Maximum (- 7, 4)

x^{3} - 9 x^{2} + 1

f (x) = \frac{- 24 x ^{2} - 20 x + 24}{( x ^{2} + 1 ) ^{2}}

f (x) = x^{2} + y^{2} + 20 x - 8 y

f (x) = x + y + \frac{8}{x y}

f (x) = - 15051 x^{2} + 47796 x + 13402

What is the extreme f(x)=(-x^2-10x-13)/(x+9) ?
The extreme f(x)=(-x^2-10x-13)/(x+9) is Minimum(-11,12),Maximum(-7,4)