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Popular >

extreme 2t^2+7t+9

Solution

extreme points

2 t^{2} + 7 t + 9

Solution

Minimum (- \frac{7}{4}, \frac{23}{8})

Solution steps

f^{'} (t) = 4 t + 7

Find intervals:

Decreasing

: - \infty < t < - \frac{7}{4},

Increasing

: - \frac{7}{4} < t < \infty

Plug

t = - \frac{7}{4}

into

2 t^{2} + 7 t + 9 : \frac{23}{8}

Minimum (- \frac{7}{4}, \frac{23}{8})

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Frequently Asked Questions (FAQ)

What is the extreme 2t^2+7t+9 ?
The extreme 2t^2+7t+9 is Minimum(-7/4 , 23/8)