What is the extreme f(x)=x^4-8x^2-7 ?

The extreme f(x)=x^4-8x^2-7 is Minimum(-2,-23),Maximum(0,-7),Minimum(2,-23)

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extreme f(x)=x^4-8x^2-7

extreme points

f (x) = x^{4} - 8 x^{2} - 7

Minimum (- 2, - 23), Maximum (0, - 7), Minimum (2, - 23)

Solution steps

f^{'} (x) = 4 x^{3} - 16 x

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{4} - 8 x^{2} - 7 : - 23

Minimum (- 2, - 23)

Plug

x = 0

into

x^{4} - 8 x^{2} - 7 : - 7

Maximum (0, - 7)

Plug

x = 2

into

x^{4} - 8 x^{2} - 7 : - 23

Minimum (2, - 23)

Minimum (- 2, - 23), Maximum (0, - 7), Minimum (2, - 23)

f (x, y) = y^{3} + 2 y^{2} x + 5 y x^{2} - 5 y

h (v, t) = 3 v t - 9 t^{2}

f (x) = \frac{( 2 x - 9 )}{x}

f (x, y) = 400 - 9 x^{2} - 36 y^{2}

f (x) = (2 - x)^{2} (0 + x)

What is the extreme f(x)=x^4-8x^2-7 ?
The extreme f(x)=x^4-8x^2-7 is Minimum(-2,-23),Maximum(0,-7),Minimum(2,-23)