What is the extreme f(x)=15+398x+184y-9x^2-2y^2-8xy ?

The extreme f(x)=15+398x+184y-9x^2-2y^2-8xy is Maximum(15,16)

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extreme f(x)=15+398x+184y-9x^2-2y^2-8xy

extreme points

f (x) = 15 + 398 x + 184 y - 9 x^{2} - 2 y^{2} - 8 x y

Maximum (15, 16)

Solution steps

Find the critical points:

(15, 16)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = 8

Check the sign of at each critical point

Check critical point

(15, 16) :

Maximum

Maximum (15, 16)

f (x) = cos (x), - \frac{π}{4} \leq x \leq \frac{π}{4}

- 3 x^{2} - 6 x + 3

f (x) = x y + \frac{8}{x}

f (x, y) = x^{(2)} - 2 x y + 4 y^{(2)} - 4 x - 2 y + 24

f (x) = \frac{2 + x}{7 - x}, - 7 \leq x \leq 0

What is the extreme f(x)=15+398x+184y-9x^2-2y^2-8xy ?
The extreme f(x)=15+398x+184y-9x^2-2y^2-8xy is Maximum(15,16)