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Popular >

extreme y=x^3-3x^2+7x-10

Solution

extreme points

y = x^{3} - 3 x^{2} + 7 x - 10

Solution

None

Solution steps

f^{'} (x) = 3 x^{2} - 6 x + 7

Find intervals:

None

None

Popular Examples

extreme f(x)=-10/3 x^3-31/2 x^2-3x+4 extreme points

f (x) = - \frac{10}{3} x^{3} - \frac{31}{2} x^{2} - 3 x + 4

extreme f(x)=(x^2+7x+13)/(x+4)extreme points

f (x) = \frac{x ^{2} + 7 x + 13}{x + 4}

extreme ((5x-8))/x extreme points

\frac{( 5 x - 8 )}{x}

extreme f(x)=sin(x),-5<= x<= 6 extreme points

f (x) = sin (x), - 5 \leq x \leq 6

extreme f(x)=(-2x^2+16)/(sqrt(16-y^2))extreme points

f (x) = \frac{- 2 x ^{2} + 16}{16 - y ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme y=x^3-3x^2+7x-10 ?
The extreme y=x^3-3x^2+7x-10 is None