What is the extreme f(x)=8+(9+5x)^{2/5} ?

The extreme f(x)=8+(9+5x)^{2/5} is Minimum(-9/5 ,8)

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extreme f(x)=8+(9+5x)^{2/5}

extreme points

f (x) = 8 + (9 + 5 x)^{\frac{2}{5}}

Minimum (- \frac{9}{5}, 8)

Solution steps

f^{'} (x) = \frac{2}{( 5 x + 9 ) ^{\frac{3}{5}}}

Find intervals:

Decreasing

: - \infty < x < - \frac{9}{5},

Increasing

: - \frac{9}{5} < x < \infty

Plug

x = - \frac{9}{5}

into

8 + (9 + 5 x)^{\frac{2}{5}} : 8

Minimum (- \frac{9}{5}, 8)

f (x, y) = 7 x^{2} + 8 y^{2} + 4 x - 5 y + 8

f (x) = - 7 sec (x), - \frac{π}{3} \leq x \leq \frac{π}{3}

f (x, y) = \frac{x y ( 9 - x - 2 y )}{3}

x^{3} + 3 x y^{2} - 3 y^{2} - 3 x^{2} + 11

0.001 x^{2} + 3.4 x - 90

What is the extreme f(x)=8+(9+5x)^{2/5} ?
The extreme f(x)=8+(9+5x)^{2/5} is Minimum(-9/5 ,8)