What is the extreme f(x)=12x-12y-2x^2-3y^2-25 ?

The extreme f(x)=12x-12y-2x^2-3y^2-25 is Maximum(3,-2)

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extreme f(x)=12x-12y-2x^2-3y^2-25

extreme points

f (x) = 12 x - 12 y - 2 x^{2} - 3 y^{2} - 25

Maximum (3, - 2)

Solution steps

Find the critical points:

(3, - 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = 24

Check the sign of at each critical point

Check critical point

(3, - 2) :

Maximum

Maximum (3, - 2)

f (x) = 3 x^{3} + 9 x^{2} - 72 x

f (x y) = x^{2} y^{3} - 2 x^{4} y

f (x) = x^{2} + 2 y^{2} - x y + 14 y

f (x) \frac{1}{( x ^{2} - 10 x + 35 ) ^{3}}

f (x) = \frac{x ^{3}}{3} + x^{2} - 3 x + 4

What is the extreme f(x)=12x-12y-2x^2-3y^2-25 ?
The extreme f(x)=12x-12y-2x^2-3y^2-25 is Maximum(3,-2)