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Popular >

extreme f(x)=(x^3-3x^2+3x+1)

Solution

extreme points

f (x) = (x^{3} - 3 x^{2} + 3 x + 1)

Solution

Saddle (1, 2)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x + 3

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{3} - 3 x^{2} + 3 x + 1 : 2

Saddle (1, 2)

Popular Examples

extreme f(x)=x^3-3x+1,-3/2 <= x<= 3 extreme points

f (x) = x^{3} - 3 x + 1, - \frac{3}{2} \leq x \leq 3

extreme 16*x-4*ln(x)extreme points

16 \cdot x - 4 \cdot ln (x)

extreme f(x,y,z)=64 extreme points

f (x, y, z) = 64

extreme f(x)=(16)/x+2pix^2 extreme points

f (x) = \frac{16}{x} + 2 π x^{2}

extreme y=x+9/x-4 extreme points

y = x + \frac{9}{x} - 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^3-3x^2+3x+1) ?
The extreme f(x)=(x^3-3x^2+3x+1) is Saddle(1,2)