What is the extreme f(x)=x^{-2}-13x^{-1} ?

The extreme f(x)=x^{-2}-13x^{-1} is Minimum(2/13 ,-169/4)

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extreme f(x)=x^{-2}-13x^{-1}

extreme points

f (x) = x^{- 2} - 13 x^{- 1}

Minimum (\frac{2}{13}, - \frac{169}{4})

Solution steps

f^{'} (x) = - \frac{2}{x ^{3}} + \frac{13}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \frac{2}{13},

Increasing

: \frac{2}{13} < x < \infty

Plug

x = \frac{2}{13}

into

x^{- 2} - 13 x^{- 1} : - \frac{169}{4}

Minimum (\frac{2}{13}, - \frac{169}{4})

f (x) = 68 x - x^{3}

f (x) = 2 x^{3} - 7

f (x) = x^{4} + 2 y^{2} - 2 x y

3 + 4 x^{2} - x^{4}

f (x, y) = (2 e^{- x^{2}} + e^{- 3 y^{2}})

What is the extreme f(x)=x^{-2}-13x^{-1} ?
The extreme f(x)=x^{-2}-13x^{-1} is Minimum(2/13 ,-169/4)