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Popular >

extreme f(x)=x^2+4x+11

Solution

extreme points

f (x) = x^{2} + 4 x + 11

Solution

Minimum (- 2, 7)

Solution steps

f^{'} (x) = 2 x + 4

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{2} + 4 x + 11 : 7

Minimum (- 2, 7)

Popular Examples

extreme f(x)=x^2+4x+10 extreme points

f (x) = x^{2} + 4 x + 10

extreme f(x)=x^2+4x+17 extreme points

f (x) = x^{2} + 4 x + 17

extreme f(x)=xsqrt(324-x^2)extreme points

f (x) = x 324 - x^{2}

extreme y=-9/4 x^2+8 extreme points

y = - \frac{9}{4} x^{2} + 8

extreme f(x,y)=y^3+6x^2y-6x^2-6y^2+3 extreme points

f (x, y) = y^{3} + 6 x^{2} y - 6 x^{2} - 6 y^{2} + 3

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+4x+11 ?
The extreme f(x)=x^2+4x+11 is Minimum(-2,7)