What is the extreme f(x)= x/(x-9),11<= x<= 13 ?

The extreme f(x)= x/(x-9),11<= x<= 13 is Maximum(11, 11/2),Minimum(13, 13/4)

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extreme f(x)= x/(x-9),11<= x<= 13

extreme points

f (x) = \frac{x}{x - 9}, 11 \leq x \leq 13

Maximum (11, \frac{11}{2}), Minimum (13, \frac{13}{4})

Solution steps

Find the critical points:

x = 11, x = 13

Domain of

\frac{x}{x - 9}, 11 \leq x \leq 13 : 11 \leq x \leq 13

Find intervals:

Decreasing

: 11 < x < 13

Plug the extreme point

x = 11

into

\frac{x}{x - 9} \Rightarrow y = \frac{11}{2}

Maximum (11, \frac{11}{2})

Plug the extreme point

x = 13

into

\frac{x}{x - 9} \Rightarrow y = \frac{13}{4}

Minimum (13, \frac{13}{4})

Maximum (11, \frac{11}{2}), Minimum (13, \frac{13}{4})

f (x) = x 1 - x

f (x) = \frac{x + 1}{2 x + x + 1}

f (x, y) = 7 x^{2} + 8 x y + 9 y^{2} + 9 x y^{2} + 5 x^{2} y

f (x) = (\frac{1}{x ^{3} - 2 x ^{2}}), 1 \leq x \leq \frac{7}{5}

e^{- (x^{2} + y^{2})} (x^{2} + 2 y^{2})

What is the extreme f(x)= x/(x-9),11<= x<= 13 ?
The extreme f(x)= x/(x-9),11<= x<= 13 is Maximum(11, 11/2),Minimum(13, 13/4)