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Popular >

extreme y=(5x^2)/((x-4)^2)

Solution

extreme points

y = \frac{5 x ^{2}}{( x - 4 ) ^{2}}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = - \frac{40 x}{( x - 4 ) ^{3}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 0

into

\frac{5 x ^{2}}{( x - 4 ) ^{2}} : 0

Minimum (0, 0)

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Frequently Asked Questions (FAQ)

What is the extreme y=(5x^2)/((x-4)^2) ?
The extreme y=(5x^2)/((x-4)^2) is Minimum(0,0)