What is the extreme f(x)=-0.3t^2+2.4t+98.2 ?

The extreme f(x)=-0.3t^2+2.4t+98.2 is Maximum(4,103)

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extreme f(x)=-0.3t^2+2.4t+98.2

extreme points

f (x) = - 0.3 t^{2} + 2.4 t + 98.2

Maximum (4, 103)

Solution steps

f^{'} (t) = - 0.6 t + 2.4

Find intervals:

Increasing

: - \infty < t < 4,

Decreasing

: 4 < t < \infty

Plug

t = 4

into

- 0.3 t^{2} + 2.4 t + 98.2 : 103

Maximum (4, 103)

f (x) = \frac{( x ^{2} - 8 )}{( x - 3 )}

f (x) = 4.3 x - 0.01 x^{2} - 8

f (x) = x^{5} - 3125 x, - 7 \leq x \leq 7

\frac{- 2 ln ( x ) - 2}{x ^{2}}

f (x) = x^{2} + \frac{200}{x}, [0, \infty]

What is the extreme f(x)=-0.3t^2+2.4t+98.2 ?
The extreme f(x)=-0.3t^2+2.4t+98.2 is Maximum(4,103)