What is the extreme f(x)=(100000)/x+75000+1000x ?

The extreme f(x)=(100000)/x+75000+1000x is Maximum(-10,55000),Minimum(10,95000)

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extreme f(x)=(100000)/x+75000+1000x

extreme points

f (x) = \frac{100000}{x} + 75000 + 1000 x

Maximum (- 10, 55000), Minimum (10, 95000)

Solution steps

f^{'} (x) = - \frac{100000}{x ^{2}} + 1000

Find intervals:

Increasing

: - \infty < x < - 10,

Decreasing

: - 10 < x < 0,

Decreasing

: 0 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = - 10

into

\frac{100000}{x} + 75000 + 1000 x : 55000

Maximum (- 10, 55000)

Plug

x = 10

into

\frac{100000}{x} + 75000 + 1000 x : 95000

Minimum (10, 95000)

Maximum (- 10, 55000), Minimum (10, 95000)

y = e^{x} - 3 e^{- x} - 4 x

f (x) = - 6 x^{3} - 54 x^{2} - 144 x - 90

f (x, y) = 25 - x^{2} - y^{2}

f (x) = (\frac{x + y - x y}{x - y + x y})

3 (x + 2) (x - 10)

What is the extreme f(x)=(100000)/x+75000+1000x ?
The extreme f(x)=(100000)/x+75000+1000x is Maximum(-10,55000),Minimum(10,95000)