What is the extreme f(x)=f(x)=ex-x,-4<= x<= 2 ?

The extreme f(x)=f(x)=ex-x,-4<= x<= 2 is Minimum(-4,-4e+4),Maximum(2,e2-2)

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extreme f(x)=f(x)=ex-x,-4<= x<= 2

extreme points

f (x) = f (x) = e x - x, - 4 \leq x \leq 2

Minimum (- 4, - 4 e + 4), Maximum (2, e 2 - 2)

Solution steps

Find the critical points:

x = - 4, x = 2

Domain of

e x - x, - 4 \leq x \leq 2 : - 4 \leq x \leq 2

Find intervals:

Increasing

: - 4 < x < 2

Plug the extreme point

x = - 4

into

e x - x \Rightarrow y = - 4 e + 4

Minimum (- 4, - 4 e + 4)

Plug the extreme point

x = 2

into

e x - x \Rightarrow y = e 2 - 2

Maximum (2, e 2 - 2)

Minimum (- 4, - 4 e + 4), Maximum (2, e 2 - 2)

f (x) = 4 x^{2} - 48 x + 190

f (x, y) = e^{9 x^{2} + 6 y^{2} + 1}

f (x) = (\frac{3 - cos ( θ )}{sin ( θ )})

f (x y) = - x^{3} - y^{2} + 3 x - 2 y

\frac{9}{8} y \frac{3}{4}

What is the extreme f(x)=f(x)=ex-x,-4<= x<= 2 ?
The extreme f(x)=f(x)=ex-x,-4<= x<= 2 is Minimum(-4,-4e+4),Maximum(2,e2-2)