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Popular >

extreme 4+(7+5x)^{2/5}

Solution

extreme points

4 + (7 + 5 x)^{\frac{2}{5}}

Solution

Minimum (- \frac{7}{5}, 4)

Solution steps

f^{'} (x) = \frac{2}{( 5 x + 7 ) ^{\frac{3}{5}}}

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{5},

Increasing

: - \frac{7}{5} < x < \infty

Plug

x = - \frac{7}{5}

into

4 + (7 + 5 x)^{\frac{2}{5}} : 4

Minimum (- \frac{7}{5}, 4)

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Frequently Asked Questions (FAQ)

What is the extreme 4+(7+5x)^{2/5} ?
The extreme 4+(7+5x)^{2/5} is Minimum(-7/5 ,4)