What is the extreme f(t)=7e^{-7t}u(t) ?

The extreme f(t)=7e^{-7t}u(t) is Saddle(0,0)

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extreme f(t)=7e^{-7t}u(t)

extreme points

f (t) = 7 e^{- 7 t} u (t)

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial t ^{2}} = 0

D (t, u) = - 49 (- 7 e^{- 7 t} t + e^{- 7 t})^{2}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

y = (x - \frac{200}{x})

f (x) = 3 x^{2} + 4 y^{2}

f (y) = 4 x^{3} y + 3 x^{2} + y^{2} + 4 - y

- 2 ln (x - 6) + 2

y = 1 + 40 x^{3} - 3 x^{5}

What is the extreme f(t)=7e^{-7t}u(t) ?
The extreme f(t)=7e^{-7t}u(t) is Saddle(0,0)