en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=120t-16t^2

Solution

extreme points

f (x) = 120 t - 16 t^{2}

Solution

Maximum (\frac{15}{4}, 225)

Solution steps

f^{'} (t) = 120 - 32 t

Find intervals:

Increasing

: - \infty < t < \frac{15}{4},

Decreasing

: \frac{15}{4} < t < \infty

Plug

t = \frac{15}{4}

into

120 t - 16 t^{2} : 225

Maximum (\frac{15}{4}, 225)

Popular Examples

extreme x^2-y^2+1 extreme points

x^{2} - y^{2} + 1

extreme f(x,y)=9x^2-2x^3+3y^2+6xy extreme points

f (x, y) = 9 x^{2} - 2 x^{3} + 3 y^{2} + 6 x y

extreme f(x)=395x^2-2370x^3,0<= x<= 0.16 extreme points

f (x) = 395 x^{2} - 2370 x^{3}, 0 \leq x \leq 0.16

extreme C(t)= t/(4t^2+11)extreme points

C (t) = \frac{t}{4 t ^{2} + 11}

extreme f(x)=2x^3+y^3+3x^2-3y-12x-4 extreme points

f (x) = 2 x^{3} + y^{3} + 3 x^{2} - 3 y - 12 x - 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=120t-16t^2 ?
The extreme f(x)=120t-16t^2 is Maximum(15/4 ,225)