What is the extreme f(x)=(e^x)/(x^7) ?

The extreme f(x)=(e^x)/(x^7) is Minimum(7,(e^7)/(823543))

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extreme f(x)=(e^x)/(x^7)

extreme points

f (x) = \frac{e ^{x}}{x ^{7}}

Minimum (7, \frac{e ^{7}}{823543})

Solution steps

f^{'} (x) = \frac{e ^{x} ( x - 7 )}{x ^{8}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = 7

into

\frac{e ^{x}}{x ^{7}} : \frac{e ^{7}}{823543}

Minimum (7, \frac{e ^{7}}{823543})

f (x) = 7 x^{4} - 2 x^{2} - 8 x + 8

f (x) = \frac{x ^{3}}{- x ^{2} + 4}

f (x) = \frac{( x ^{2} - 63 )}{x - 8}

x^{3} + 8 y^{3} - 6 x y + 5

f (x) = 4 x^{3} - 60 x^{2} + 200 x

What is the extreme f(x)=(e^x)/(x^7) ?
The extreme f(x)=(e^x)/(x^7) is Minimum(7,(e^7)/(823543))