en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(3x^2+6)^2

Solution

extreme points

f (x) = (3 x^{2} + 6)^{2}

Solution

Minimum (0, 36)

Solution steps

f^{'} (x) = 12 x (3 x^{2} + 6)

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

(3 x^{2} + 6)^{2} : 36

Minimum (0, 36)

Popular Examples

extreme f(x,y)=x^2+4xy+5y^2-7x+9y-10 extreme points

f (x, y) = x^{2} + 4 x y + 5 y^{2} - 7 x + 9 y - 10

extreme f(x)=9x-18cos(x),-2<= x<= 0 extreme points

f (x) = 9 x - 18 cos (x), - 2 \leq x \leq 0

extreme f(x)=2x^2-4x,0<= x<= 3 extreme points

f (x) = 2 x^{2} - 4 x, 0 \leq x \leq 3

extreme x^2-18x+79 extreme points

x^{2} - 18 x + 79

extreme f(x)=3x^4-294x^2+3,-8<= x<= 8 extreme points

f (x) = 3 x^{4} - 294 x^{2} + 3, - 8 \leq x \leq 8

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(3x^2+6)^2 ?
The extreme f(x)=(3x^2+6)^2 is Minimum(0,36)