What is the extreme f(x)=x^3+2x^2-4x+7 ?

The extreme f(x)=x^3+2x^2-4x+7 is Maximum(-2,15),Minimum(2/3 , 149/27)

Popular >

extreme f(x)=x^3+2x^2-4x+7

extreme points

f (x) = x^{3} + 2 x^{2} - 4 x + 7

Maximum (- 2, 15), Minimum (\frac{2}{3}, \frac{149}{27})

Solution steps

f^{'} (x) = 3 x^{2} + 4 x - 4

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < \frac{2}{3},

Increasing

: \frac{2}{3} < x < \infty

Plug

x = - 2

into

x^{3} + 2 x^{2} - 4 x + 7 : 15

Maximum (- 2, 15)

Plug

x = \frac{2}{3}

into

x^{3} + 2 x^{2} - 4 x + 7 : \frac{149}{27}

Minimum (\frac{2}{3}, \frac{149}{27})

Maximum (- 2, 15), Minimum (\frac{2}{3}, \frac{149}{27})

f (x, y) = - 4 x y + 2 x^{2} - 10 y^{2} - 4 y^{3} - 1

4 sin (2 x), - 2 π \leq x \leq π

0.3 x^{2} - 66 x + 15239

a (- 6 - 0)^{2}

f (x, y) = 2 x y - \frac{x ^{2} y}{3} - \frac{2 x y ^{2}}{3}

What is the extreme f(x)=x^3+2x^2-4x+7 ?
The extreme f(x)=x^3+2x^2-4x+7 is Maximum(-2,15),Minimum(2/3 , 149/27)