What is the extreme p(x)=12x^4-62x^3+ax^2-98x+30 ?

The extreme p(x)=12x^4-62x^3+ax^2-98x+30 is None

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extreme p(x)=12x^4-62x^3+ax^2-98x+30

extreme points

p (x) = 12 x^{4} - 62 x^{3} + a x^{2} - 98 x + 30

None

Solution steps

Find the critical points:

None

12 x^{4} - 62 x^{3} + a x^{2} - 98 x + 30

has no critical points, therefore there are no extreme points

None

y = 3 z^{2} - 3 x^{2}

4 - y^{3} - x^{2} - 3 x y

\frac{10 x ^{3} - 2}{2 x ^{3} + 5 x ^{2} + 9 x}

- 6 x^{2} + 336 x - 4320

What is the extreme p(x)=12x^4-62x^3+ax^2-98x+30 ?
The extreme p(x)=12x^4-62x^3+ax^2-98x+30 is None