What is the parity (x,1,(x-1))/((x^2-4)) ?

The parity (x,1,(x-1))/((x^2-4)) is Neither even nor odd

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 from the left of (x-1)/(x^2-4)

parity

\frac{x , 1 , ( x - 1 )}{( x ^{2} - 4 )}

Neither even nor odd

Solution steps

f (- x) : \frac{( - x ) , 1 , ( - x - 1 )}{( - x ) ^{2} - 4}

- f (x) : - \frac{x , 1 , ( x - 1 )}{x ^{2} - 4}

Check parity of

\frac{x , 1 , ( x - 1 )}{x ^{2} - 4}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

g (f) = 21 f

y = 5 x^{2} + 40 x + 64

f (x) = x^{2}

f (x) = - \frac{1}{x}, (1, 2)

y = sec (x)

What is the parity (x,1,(x-1))/((x^2-4)) ?
The parity (x,1,(x-1))/((x^2-4)) is Neither even nor odd