What is the inverse of 5y+4=((x+3)^2+1)/2 ?

The inverse of 5y+4=((x+3)^2+1)/2 is sqrt(2x-1)-3,-sqrt(2x-1)-3

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Find the Inverse 5y+4=(x+3)^2+1/2

inverse

5 y + 4 = \frac{( x + 3 ) ^{2} + 1}{2}

2 x - 1 - 3, - 2 x - 1 - 3

Solution steps

y = \frac{( x + 3 ) ^{2} + 1}{2}

Replace

x

with

y

x = \frac{( y + 3 ) ^{2} + 1}{2}

Solve for

y, x = \frac{( y + 3 ) ^{2} + 1}{2}

2 x - 1 - 3, - 2 x - 1 - 3

y = cot (x)

3 x - 4 y = 8

2 y - 3 x = 8

6 x - 4 y = 8

f (x) = x - 3

What is the inverse of 5y+4=((x+3)^2+1)/2 ?
The inverse of 5y+4=((x+3)^2+1)/2 is sqrt(2x-1)-3,-sqrt(2x-1)-3